Solve for c a(b-c)=d - Math Solver

$a (b - c) = d$

Divide each term by $a$ and simplify.

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Divide each term in $a (b - c) = d$ by $a$ .

$\frac{a (b - c)}{a} = \frac{d}{a}$

Cancel the common factor of $a$ .

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Cancel the common factor.

$\frac{a (b - c)}{a} = \frac{d}{a}$

Divide $b - c$ by $1$ .

$b - c = \frac{d}{a}$

Subtract $b$ from both sides of the equation.

$- c = \frac{d}{a} - b$

Multiply each term in $- c = \frac{d}{a} - b$ by $- 1$

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Multiply each term in $- c = \frac{d}{a} - b$ by $- 1$ .

$(- c) \cdot - 1 = \frac{d}{a} \cdot - 1 + (- b) \cdot - 1$

Multiply $(- c) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 c = \frac{d}{a} \cdot - 1 + (- b) \cdot - 1$

Multiply $c$ by $1$ .

$c = \frac{d}{a} \cdot - 1 + (- b) \cdot - 1$

Simplify each term.

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Combine $\frac{d}{a}$ and $- 1$ .

$c = \frac{d \cdot - 1}{a} + (- b) \cdot - 1$

Move $- 1$ to the left of $d$ .

$c = \frac{- 1 \cdot d}{a} + (- b) \cdot - 1$

Move the negative in front of the fraction.

$c = - \frac{d}{a} + (- b) \cdot - 1$

Multiply $(- b) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$c = - \frac{d}{a} + 1 b$

Multiply $b$ by $1$ .

$c = - \frac{d}{a} + b$

Solve for c a(b-c)=d

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