Solve by Substitution 3x-9y=21 , -2x+6y=-14

$3 x - 9 y = 21$ , $- 2 x + 6 y = - 14$

Solve for $x$ in the first equation.

Tap for more steps…

Add $9 y$ to both sides of the equation.

$3 x = 21 + 9 y$

$- 2 x + 6 y = - 14$

Divide each term by $3$ and simplify.

Tap for more steps…

Divide each term in $3 x = 21 + 9 y$ by $3$ .

$\frac{3 x}{3} = \frac{21}{3} + \frac{9 y}{3}$

$- 2 x + 6 y = - 14$

Cancel the common factor of $3$ .

Tap for more steps…

Cancel the common factor.

$\frac{3 x}{3} = \frac{21}{3} + \frac{9 y}{3}$

$- 2 x + 6 y = - 14$

Divide $x$ by $1$ .

$x = \frac{21}{3} + \frac{9 y}{3}$

$- 2 x + 6 y = - 14$

$x = \frac{21}{3} + \frac{9 y}{3}$

$- 2 x + 6 y = - 14$

Simplify each term.

Tap for more steps…

Divide $21$ by $3$ .

$x = 7 + \frac{9 y}{3}$

$- 2 x + 6 y = - 14$

Cancel the common factor of $9$ and $3$ .

Tap for more steps…

Factor $3$ out of $9 y$ .

$x = 7 + \frac{3 (3 y)}{3}$

$- 2 x + 6 y = - 14$

Cancel the common factors.

Tap for more steps…

Factor $3$ out of $3$ .

$x = 7 + \frac{3 (3 y)}{3 (1)}$

$- 2 x + 6 y = - 14$

Cancel the common factor.

$x = 7 + \frac{3 (3 y)}{3 \cdot 1}$

$- 2 x + 6 y = - 14$

Rewrite the expression.

$x = 7 + \frac{3 y}{1}$

$- 2 x + 6 y = - 14$

Divide $3 y$ by $1$ .

$x = 7 + 3 y$

$- 2 x + 6 y = - 14$

$x = 7 + 3 y$

$- 2 x + 6 y = - 14$

$x = 7 + 3 y$

$- 2 x + 6 y = - 14$

$x = 7 + 3 y$

$- 2 x + 6 y = - 14$

$x = 7 + 3 y$

$- 2 x + 6 y = - 14$

$x = 7 + 3 y$

$- 2 x + 6 y = - 14$

Replace all occurrences of $x$ in $- 2 x + 6 y = - 14$ with $7 + 3 y$ .

$x = 7 + 3 y$

$- 2 (7 + 3 y) + 6 y = - 14$

Simplify $- 2 (7 + 3 y) + 6 y$ .

Tap for more steps…

Simplify each term.

Tap for more steps…

Apply the distributive property.

$x = 7 + 3 y$

$- 2 \cdot 7 - 2 (3 y) + 6 y = - 14$

Multiply $- 2$ by $7$ .

$x = 7 + 3 y$

$- 14 - 2 (3 y) + 6 y = - 14$

Multiply $3$ by $- 2$ .

$x = 7 + 3 y$

$- 14 - 6 y + 6 y = - 14$

$x = 7 + 3 y$

$- 14 - 6 y + 6 y = - 14$

Combine the opposite terms in $- 14 - 6 y + 6 y$ .

Tap for more steps…

Add $- 6 y$ and $6 y$ .

$x = 7 + 3 y$

$- 14 + 0 = - 14$

Add $- 14$ and $0$ .

$x = 7 + 3 y$

$- 14 = - 14$

$x = 7 + 3 y$

$- 14 = - 14$

$x = 7 + 3 y$

$- 14 = - 14$

Since $- 14 = - 14$ , the equation will always be true.

$x = 7 + 3 y$

Always true

Remove any equations from the system that are always true.

$x = 7 + 3 y$

Solve by Substitution 3x-9y=21 , -2x+6y=-14

Mathematic

Solve My Algebra Homework

Best Quality

Forgot about Math Problem

Best Solution